What is the total resistance of 560 Ω, 1 kΩ, and 3.3 kΩ in series?

What is the total resistance of 560 Ω, 1 kΩ, and 3.3 kΩ in series?

• A. 3,060 Ω
• B. 4,860 Ω
• C. 5,120 Ω
• D. 4,260 Ω

Answer: (B)

In a series circuit, you simply add each resistance because the same current flows through every component and the voltages add across them. Convert all values to the same unit: 1 kΩ is 1000 Ω and 3.3 kΩ is 3300 Ω. Then add: 560 Ω + 1000 Ω + 3300 Ω = 4860 Ω. So the total resistance is 4,860 Ω (4.86 kΩ). The other options would result from mis-converting or mis-summing, but the correct approach is to add the resistances in series.

In a series circuit, you simply add each resistance because the same current flows through every component and the voltages add across them. Convert all values to the same unit: 1 kΩ is 1000 Ω and 3.3 kΩ is 3300 Ω. Then add: 560 Ω + 1000 Ω + 3300 Ω = 4860 Ω. So the total resistance is 4,860 Ω (4.86 kΩ). The other options would result from mis-converting or mis-summing, but the correct approach is to add the resistances in series.